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Thread starter liz Start date Nov 22, The mass is constant, and there is a varying force. So would the mass be the dependent value y-axis and the acceleration be the independent value x-axis?
I think the mass is the dependent value so when I graphed it the line went straight across horizontal. Is this right? I'm really confused because I thought acceleration was inversely proportional to mass, so it shouldn't be a linear relationship?
What does acceleration verses reciprocal mass means?
Then, if your mass is constant, then the value of mass doesnt change. Its a number like 7 or 8 or 9. TO graph mass vs acceleration is to say mass on the y axis and acceleration on the X axis. So I think it should be something like a straight horizontal line like you said. This seems logical because your y-value that is mass stays constant but you acceleration changes, which is your x value.
If this is what your graph depicts then it seems right. Mathemagician said:. You said yourself that the mass is constant. This means that for any point P a,m where a is acceleration and m is mass, you have the same y value m for any x value a. This is why you got a horizontal line when you graphed mass vs.
You must log in or register to reply here. Related Threads on What is the shape of a mass vs. Shape of mass vs acceleration graph? Last Post Aug 20, Replies 2 Views 2K.I have been told to make the graph shown here of mass against reciprocal acceleration. A y-intercept occurs when there is a error that applies to all tests systematic error.
This could have been caused by a range of errors when conducting the experiment. A few possible ideas are an extra force applied to hold the cart in place which could be due to the ramp being on a slight slope, holding the cart with your hand. The error could have also be used by the scale being calibrated incorrectly, you measuring the mass incorrectly. There are a range of possibilities that could cause the intercept.
I suggest thinking of something that affected all tests and using that as a reason. The equation in the legend is of the trendline for these data. Eric C. Sep 26, In this case you have a small positive y-intercept. Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2?
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The graph forms a hyperbola. Im not sure why its a hyperbola as opposed to a straight like that shows the a decreases as the mass increases for the level of uncertainty, i have to find the level of uncertainty of the applied force over 6 tests. Delphi51 Homework Helper. It looks like you did an experiment where you applied the same force to a series of different masses and measured the acceleration.
Then the graph should be a straight line with slope equal to the Force. If the data points form a perfect straight line, then you have no uncertainty in the force.
If the points don't fit a straight line very well, then you have a lot of uncertainty. One way to measure the uncertainty is to draw a straight line through the middle of the cloud of points as best you can.
Then draw another straight line that is as steep as you can draw while still coming close to all the data points. Ideally, you would have error bars instead of data points and make your extreme slope line come within the range of most of the error bars. The difference between the best slope and the extreme one is your uncertainty in the force.
A more sophisticated approach is to put all the data points into a graphing calculator and let it draw the graph and calculate the variance or standard deviation - these are good measurements of the uncertainty.
I think the better way to determine uncertainty is to develop the uncertainty from the methodology of your experiment, - i.
Then if your variances lie within that, you know you have a sounder confirmation of your theoretical to actual. You must log in or register to reply here. Related Threads on Acceleration vs mass graph shape? Shape of mass vs acceleration graph? Last Post Aug 20, To determine the relationship between force, mass, and acceleration using a cart attached to a pulley with varying weights.
If the mass of the weights attached to the pulley is increased, the force exerted on the cart and the acceleration of the cart will also increase. Is the graph of force vs.
If so, what is the value of the slope? Yes, the graph produces nearly a straight line; the correlation for a linear fit is 0. The value of the slope is 0.
What are the units of the slope of force vs. Simplify the units of the slope to fundamental units m, kg, s. What does the slope represent? The units of the slope of force vs. This simplifies to kg. The slope represents the mass of the pulley. What is the total mass of the system both with and without extra weight that you measured?
The total mass of the system without the extra weight was 0. How does the slope of your graph compare percent difference with the total mass of the system that you measured? The slope of the graph without any added weights was 0. The slope of the graph with the added weights was 0.
Are the net force on an object and the acceleration of the object directly proportional? Write a general equation that relates all three variables: force, mass, and acceleration.
The overall goal of the lab was to determine and show the relationship between force, mass, and acceleration. The goal was achieved using a cart and pulley system with varying weights to measure force and acceleration. The forces and accelerations collected were then graphed against each other the construct a linear fit line, whose slope showed the mass of the system the cart, sensor, and any added weights.
This value could then be compared to the mass calculated from the force of the free hanging system. The force and acceleration from each trial run could also be analyzed to show any relationship between the two values.Joy Paul. The three attached graphs highlight the relationships between force, mass and acceleration.
Analyzing the first graph of constant applied force shows that as mass was increased, acceleration decreased. As the negative slope of the graph indicates, there is an inverse relationship between the two. Manipulation of the data by plotting the inverse mass vs. Although mathematically, this would make sense, since adding mass makes the denominator of the equation larger, thus decreasing the value of the acceleration.
These variations are still only at maximum. One likely reason for these differences is that the area of interest of the recorded acceleration was chosen by my lab partner and me as a judgment call on where the graph seemed to show the steadiest rate of change in velocity.
The computer program then averaged this range of data chosen by us. An average of data will be different than an almost instantaneous acceleration of a particular mass being pulled upon by a constant force.
Analyzing the graph of constant mass shows that as the applied force was increased, acceleration also increased. The positive, linear slope shows that there is a direct, linear relationship between acceleration and force. This agrees with the mathematical equation, since a constant mass is being divided into a larger numerator, or force, acceleration should increase.
To increase applied force, we had to increase the mass of the system. Although by comparison, the additional mass was small, it never the less impacted our data. Our observations show that both force and mass affect acceleration. Additional mass decreases acceleration and increasing the applied force increases acceleration. Although the slope of the graph for constant mass is steeper than that for constant forcethis should not imply that one has a greater effect on acceleration than the other.
By plotting the inverse of the mass vs. The lack of a straight line does not deny or support this direct relationship. Further manipulations are needed to determine the exact relationship between mass and acceleration. Data collection errors reported above need to be eliminated, along with far most extensive data collection to identify whether one factor does indeed affect acceleration greater than the other.
We can, however, based on our limited observations, state that mass and acceleration seem to be inversely proportional, and applied force and acceleration seem to be directly proportional.Think of it this way: you apply some force onto an iron ball, and apply the same force on a plastic ball they are of equal volume.
Investigation 2.3.1: The Relationship Involving Acceleration, Net Force, and Mass Answers
Which one moves faster, and which one moves slower? The answer is obvious: the iron ball will accelerate slower and travel slower, while the plastic ball is faster. The iron ball has a greater mass, so the force which makes it accelerate is deduced more. The plastic ball has a smaller mass, so the force applied is divided by a smaller number. Say we wish to keep a force F exerted by an object constant. If the mass m of the object doubles, what must happen to the object's acceleration a to keep F unchanged?
Thus, the LHS also doubles, meaning we get double the force:. This is an example of direct proportionality between F and m. If m doubles, F responds by doubling as well. But we want to keep the force the same; we don't want 2Fwe want F.
So we need to divide the LHS by 2. And to do that, we must divide the RHS by 2 as well. This is an example of inverse proportionality. When the force is taken as a constant, if mass doubles, acceleration must be halved. It's now easy to see mathematically that a and m are inversely proportional, because each is a multiple of the other's inverse that multiple being F itself.
Why is acceleration inversely proportional to mass? Physics 2D Motion Relative Motion. Apr 28, Explanation: an object moving at a velocity of x carries the force of its mass times its speed. I hope this helps you a bit. Geoff K. Explanation: Say we wish to keep a force F exerted by an object constant. The answer is: the object's acceleration must be halved.
Related questions Why is acceleration negative in a free fall? When is acceleration constant? Why is acceleration a vector quantity?What does the slope of an inverse of mass vs acceleration graph represent? All Rights Reserved. The material on this site can not be reproduced, distributed, transmitted, cached or otherwise used, except with prior written permission of Multiply.
Hottest Questions. Previously Viewed. Unanswered Questions. Wiki User October 16, PM. If you are applying a constant net force to an object and measuring the acceleration as you change mass, the graph of acceleration y-axis, dependent variable vs mass x-axis, independent variable would be hyperbolic.
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